Chemical Kinetics and Nuclear ChemistryHard
Question
As the initial concentration increases from 0.75 to 1.55 M in a reaction, t1/2 decreases from 60 to 29 s. The order of the reaction is
Options
A.Zero
B.first
C.second
D.third
Solution
$t_{1/2}\alpha\left\lbrack A_{0} \right\rbrack^{1 - n}$
$\Rightarrow \frac{29}{60} = \left( \frac{1.55}{0.75} \right)^{1 - n} \Rightarrow n \approx 2$
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