For hypothetical reaction A → B takes place according to$$A\overset{\quad K_{1}\quad}{\leftleftarrow

Question

For hypothetical reaction A → B takes place according to

$$A\overset{\quad K_{1}\quad}{\leftleftarrows}C\left( \text{fast} \right) $$$A + C\overset{\quad K_{2}\quad}{\rightarrow}B\left( \text{slow} \right)$

The rate of reaction is (K₁ is equilibrium constant)

Accepted Answer

$r = K_{2}\lbrack Abrack\lbrack Cbrack	ext{ and }K_{1} = \frac{\lbrack Cbrack}{\lbrack Abrack}$$	herefore r = K_{1}K_{2}\lbrack Abrack^{2}$

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