Chemical Kinetics and Nuclear ChemistryHard
Question
For hypothetical reaction A → B takes place according to
$$A\overset{\quad K_{1}\quad}{\leftleftarrows}C\left( \text{fast} \right) $$$A + C\overset{\quad K_{2}\quad}{\rightarrow}B\left( \text{slow} \right)$
The rate of reaction is (K1 is equilibrium constant)
Options
A.K2[B][C]
B.K1K2[A]
C.K1K2[A]2
D.K1[B][C]
Solution
$r = K_{2}\lbrack A\rbrack\lbrack C\rbrack\text{ and }K_{1} = \frac{\lbrack C\rbrack}{\lbrack A\rbrack}$
$\therefore r = K_{1}K_{2}\lbrack A\rbrack^{2}$
Create a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
Consider following reaction, Zn + 2H+ → Zn2+ + H2Half-life period is independent of concentration of Zn at constan...Decomposition of A is a first order reaction at $T(K)$ and is given by $A(g) \rightarrow B(g) + C(g)$. In a closed 1 L v...is a stable isotope. is expressed to disintegrate by :...The rate law for the dimerisation of NO2 is = k [NO2]2which of the following changes will change the value of the specif...When the concentration of reactant in the reaction A → B is increased by 8 times, the rate increases only by 2 times. Th...