JEE AdvancedThermodynamicsMedium
Question
Standard entropies of X2, Y2 and XY3 are 60, 40 and 50 JK-1 mol-1 respectively. For the reaction
y2 ⇋ XY3 ; ᐃH = - 30kJ , to be at equilibrium, the temperature should be
y2 ⇋ XY3 ; ᐃH = - 30kJ , to be at equilibrium, the temperature should beOptions
A.750 K
B.1000 K
C.1250 K
D.500 K
Solution
For the reaction,
y2 ⇋ XY3 ; ᐃH = - 30kJ
ᐃSo = So(XY3) -
= 50 -
= 50 - [30 + 60]
= 50 - 90
= - 40 JK-1 mol-1
We know that,
ᐃGo = ᐃHo - T ᐃSo
At equilibrium,
ᐃGo = 0
ᐃH = TᐃSo
T =
= 750 K
y2 ⇋ XY3 ; ᐃH = - 30kJᐃSo = So(XY3) -
= 50 -
= 50 - [30 + 60]
= 50 - 90
= - 40 JK-1 mol-1
We know that,
ᐃGo = ᐃHo - T ᐃSo
At equilibrium,
ᐃGo = 0
ᐃH = TᐃSo
T =
= 750 K
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