NEETThermodynamicsHard
Question
Calculate change in internal energy if
ᐃH = - 92.2kJ, P = 40 atm and ᐃV = - 1L.
ᐃH = - 92.2kJ, P = 40 atm and ᐃV = - 1L.
Options
A.- 42 kJ
B.- 88 kJ
C.+ 88 kJ
D.+ 42 kJ
Solution
ᐃH = - 92.2kJ , P = 40atm, ᐃV = - 1L
Using ᐃH = ᐃE + PᐃV
⇒ ᐃE = ᐃH - PᐃV
=(- 92.2 kJ) - (40 atm) (-1L) ×
= 92.2kJ + (40 atm L) ×
= - 92200J + 405.66J - 88149.34J
= - 88.149kJ ≈ - 88kJ
Using ᐃH = ᐃE + PᐃV
⇒ ᐃE = ᐃH - PᐃV
=(- 92.2 kJ) - (40 atm) (-1L) ×
= 92.2kJ + (40 atm L) ×
= - 92200J + 405.66J - 88149.34J
= - 88.149kJ ≈ - 88kJ
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