A quantity of 70 calories of heat is required to raise the temperature of 2 mole of an ideal gas at

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A quantity of 70 calories of heat is required to raise the temperature of 2 mole of an ideal gas at constant pressure from 40°C to 50°C. The amount of heat required to raise the temperature of the same gas through the same range at constant volume is

Accepted Answer

$C_{P,m} = \frac{q_{p}}{n.\Delta T} = \frac{70}{2 \times 10} = \frac{7}{2}\text{ cal}$

$\therefore C_{v,m} = \frac{7}{2} - 2 = \frac{3}{2}\text{ cal}$

Now, $q_{v} = n.C_{v,m}.\Delta T = 2 \times \frac{3}{2} \times 10 = 30\text{ cal}$

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