ThermodynamicsHard
Question
A quantity of 70 calories of heat is required to raise the temperature of 2 mole of an ideal gas at constant pressure from 40°C to 50°C. The amount of heat required to raise the temperature of the same gas through the same range at constant volume is
Options
A.90 calorie
B.70 calorie
C.50 calorie
D.30 calorie
Solution
$C_{P,m} = \frac{q_{p}}{n.\Delta T} = \frac{70}{2 \times 10} = \frac{7}{2}\text{ cal}$
$\therefore C_{v,m} = \frac{7}{2} - 2 = \frac{3}{2}\text{ cal}$
Now, $q_{v} = n.C_{v,m}.\Delta T = 2 \times \frac{3}{2} \times 10 = 30\text{ cal}$
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