ElectrochemistryHard
Question
A big irregular shaped vessel contained water, conductivity of which was 2.56 × 10−3 S−1m−1. 585 g of NaCl was then added to the water and conductivity after the addition of NaCl, was found to be 3.06 × 10−3 S−1m−1. The molar conductivity of NaCl at this concentration is 1.5 × 10−2 S−1m2 mol−1. The capacity of vessel if it is fulfilled with water, is
Options
A.3 × 104 L
B.30 L
C.3 × 108 L
D.3 × 105 L
Solution
$\Lambda_{m} = \frac{K}{C} \Rightarrow 1.5 \times 10^{- 2} = \frac{3.06 \times 10^{- 3} - 2.56 \times 10^{- 3}}{C}$
$\therefore C = \frac{1}{30}\text{mol}m^{- 3} = \frac{1}{30} \times 10^{- 3}\text{ mol.}\text{l}^{- 1} = \frac{585/58.5}{V} $$$\therefore V = 3 \times 10^{5}\text{ L}$$
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
MnO4- + 8H+ + 5e- → Mn2+ + 4H2O, If H+ concentration is decreased from 1 M to 10-4 M at 25oC, where as concentrati...Which one of the following statements is incorrect regarding an electrochemical cell?...EMF of a cell in terms of reduction potental of its left and right electrodes is...Consider the following Galvanic cell as shown in figure. By what value the cell voltage change when concentration of ion...For the process: Cu2+ + 2e− → Cu; log[Cu2+] vs. Ered graph is shown in the figure, where OA = 0.34 V. The electrode pote...