ElectrochemistryHard
Question
Consider the following Galvanic cell as shown in figure.
By what value the cell voltage change when concentration of ions in anode and cathodic compartments both increased by factor of 10 at 298 K
By what value the cell voltage change when concentration of ions in anode and cathodic compartments both increased by factor of 10 at 298 K
Options
A.+ 0.0591
B.- 0.0591
C.- 0.1182
D.0
Solution
Ecell = Eocell - 
log10[H+] [Cl-] and E′cell = - 
log10 100[H+] [Cl-].
E′cell - Ecell = - 2 × 0.0591 = - 0.1182.
log10[H+] [Cl-] and E′cell = - log10 100[H+] [Cl-].E′cell - Ecell = - 2 × 0.0591 = - 0.1182.
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Assuming that copper contains only iron, silver and gold as impurities. After passage of 12.4 A for 4825 s, the mass of ...Zn Amalgam is prepared by electrolysis of aqueous ZnCl2 using Hg cathode (9gm). How much current is to be passed through...Faraday′s laws of electrolysis are related to the :...The value of molar conductivity of HCl is greater than that of NaCl at a particular temperature because...A current of 2.0 ampere passed for 5 hours through a molten tin salt deposits 22.2 gm of metal. The oxidation number of ...