ElectrochemistryEasy
Question
EMF of a cell in terms of reduction potental of its left and right electrodes is
Options
A.E = Eleft - Eright
B.E = Eleft + Eright
C.E = Eright - Eleft
D.E = - (Eright + Eleft)
Solution
Ecell = Reduction potential of cathode (right) - reduction potential of anode (left)
= Eright - Eleft
= Eright - Eleft
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