ElectrochemistryEasy

Question

EMF of a cell in terms of reduction potental of its left and right electrodes is

Options

A.E = E_left - E_right

B.E = E_left + E_right

C.E = E_right - E_left

D.E = - (E_right + E_left)

Solution

E_cell = Reduction potential of cathode (right) - reduction potential of anode (left)
= E_right - E_left

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