ElectrochemistryHard
Question
Calculate the quantity of electricity that would be required to reduce 12.3 g of nitrobenzene to aniline if the current efficiency for the process is 50%. If the potential drop across the cell is 3.0 V, how much energy will be consumed?
Options
A.0.3 F, 86.85 kJ
B.0.6 F, 173.7 kJ
C.1.2 F, 347.4 kJ
D.0.6 F, 173.7 kJ
Solution
$\frac{w}{E} = \frac{Q}{F} \Rightarrow \frac{12.3}{123} \times 6 = \frac{Q \times 0.5}{F} \Rightarrow Q = 1.2\text{ F}$
and Energy consumed = 1.2 F × 3.0 V = 347.4 KJ
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