ElectrochemistryMedium

Question

In the lead storage battery, the anode reaction is Pb(s) + HSO4− + H2O → PbSO4(s) + H3O+ + 2e−. How many grams of Pb will be used up to deliver 1 A for 100 h? (Pb = 208)

Options

A.776 g
B.388 g
C.194 g
D.0.1 g

Solution

$n_{eq} = \frac{Q}{F} \Rightarrow \frac{w}{208} \times 2 = \frac{1 \times 100 \times 3600}{96500} \Rightarrow w \approx 388\text{ gm}$

Create a free account to view solution

View Solution Free
Topic: Electrochemistry·Practice all Electrochemistry questions

More Electrochemistry Questions

For a cell reaction involving two electron change, the standard EMF of the cell is 0.295 V at 2oC. The equilibrium const...The cell reaction for the given cell is spontaneous if Pt, Cl2 (P1 atm) |Cl−|Cl2 (P2 atm), Pt...The potential of the Daniell cell, Zn Cu was reported by Buckbee, Surdzial and Metz as Eo = 1.1028 - 0.641 × 10-3 T...If the molar conductivity ( $\Lambda_{m}$ ) of a $0.050\text{ }mol{\text{ }L}^{- 1}$ solution of a monobasic weak acid i...Zinc granules are added in excess to a 500 ml of 1.0 M nickel nitrate solution at 25°C until the equilibrium is reached....