Two students use same stock solution of ZnSO4 but different solutions of CuSO4. The EMF of one cell

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Two students use same stock solution of ZnSO4 but different solutions of CuSO4. The EMF of one cell is 0.03 V higher than the other. The concentration of CuSO4 in the cell with higher EMF value is 0.5 M. The concentration of CuSO4 in the other cell is (2.303 RT/F = 0.06)

Accepted Answer

$0.03 = \frac{0.06}{2}.\log\frac{\left\lbrack Cu^{2 +} \right\rbrack_{\text{Higher}}}{\left\lbrack Cu^{2 +} \right\rbrack_{\text{Lower}}} = 0.3.\log\frac{0.5}{\left\lbrack Cu^{2 +} \right\rbrack_{\text{Lower}}}$

$\therefore\left\lbrack Cu^{2 +} \right\rbrack_{\text{lower}} = 0.05\text{ M}$

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