ElectrochemistryHard
Question
A student made the following observations in the laboratory:
(I) Clean copper metal did not react with 1 M – Pb(NO3)2 solution.
(II) Clean lead metal dissolves in 1 M – AgNO3 solution and crystals of Ag metal appeared.
(III) Clean silver metal did not react with 1 M – Cu(NO3)2 solution.
The order of decreasing reducing character of the three metals is
Options
A.Cu > Pb > Ag
B.Cu > Ag > Pb
C.Pb > Cu > Ag
D.Pb > Ag > Cu
Solution
(I) Cu cannot reduce Pb
(II) Pb can reduce Ag
(III) Ag cannot reduce Cu.
Hence, reducing power: Pb > Cu > Ag
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Consider the cell: Ag(s), AgCl(s)|KCl (0.1 M)|Hg2Cl2(s), Hg(l). The cell potential...Which of the following is not true about e.m.f. of a cell ?...The Eo in the given figure is,...For the cell reaction: 4Br− + O2 + 4H+ $\rightleftharpoons$ 2Br2 + 2H2O; E° = 0.18 V. The value of (log KC) at 298 K is ...The standard e.m.f of a cell, involving one electron change is found to be 0.591 V at 25oC. The equilibrium constant of ...