ElectrochemistryHard

Question

Equivalence conductance at infinite dilution of NH4Cl, NaOH and NaCl are 129.8, 217.4 and 108.9 Ω−1 cm2 mol−1, respectively. If the equivalent conductance of 0.01 N solution of NH4OH is 9.532 Ω−1 cm2 mol−1, then the degree of dissociation of NH4OH at this temperature is

Options

A.0.04%
B.2.1%
C.4.0%
D.44.7%

Solution

$\Lambda_{eq\left( NH_{4}OH \right)}^{o} = \Lambda_{eq\left( NH_{4}Cl \right)}^{o} + \Lambda_{eq(NaOH)}^{o} - \Lambda_{eq(NaCl)}^{o}$

= 129.8 + 217.4 – 108.9 = 238.3 ohm–1 cm2 mol–1

Now, $\alpha = \frac{\lambda_{eq}}{\lambda_{eq}^{o}} = \frac{9.532}{238.3} = 0.04 = 4\%$

Create a free account to view solution

View Solution Free
Topic: Electrochemistry·Practice all Electrochemistry questions

More Electrochemistry Questions

For the reaction: H2 (1 bar) + 2AgCl(s) $\rightleftharpoons$ 2Ag(s) + 2H+ (0.1 M) + 2Cl− (0.1 M); ΔG0 = − 48,250 J at 25...In hydrogen - oxygen fuel cell, combustion of hydrogen occurs to...Consider the following statements:(I) is more stable than (II) is more stable than (III) is more stable than (IV) is mor...A student made the following observations in the laboratory:(I) Clean copper metal did not react with 1 M – Pb(NO3)2 sol...What is cell entropy change of the following cell ?Pt(s) | H2 (g) | CH3COOH, HCl || KCl (aq) | Hg2Cl2 (s) | Hg P = 1 atm...