ElectrochemistryHard
Question
Options
A.0
B.1.1
C.1.16
D.1.16
Solution
(1)
E = 1.1 -
log 
(2)
1.109 = 1.100 - log 
[Cu2+] = 0.2 M
áƒn = 0.2 × 0.1 - 0.1 × 0.1 = 0.01
w = 0.01 × 135 = 13.5 gm
(3)
ne =
= 0.012
E = 1.1 -
log 
E = 1.1 -
log (2)
1.109 = 1.100 -
log [Cu2+] = 0.2 M
áƒn = 0.2 × 0.1 - 0.1 × 0.1 = 0.01
w = 0.01 × 135 = 13.5 gm
(3)
ne =
= 0.012E = 1.1 -
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