ElectrochemistryHard
Question
During the electrolysis of 0.1 M – CuSO4 solution using copper electrodes, a depletion of Cu2+ occurs near the cathode with a corresponding excess near the anode, owing to inefficient stirring of the solution. If the local concentration of Cu2+ near the anode and cathode are, respectively, 0.12 M and 0.08 M, the back EMF developed at 298 K is (log 1.5 = 0.18, 2.303 RT/F = 0.06)
Options
A.0.33 V
B.5.4 mV
C.2.7 mV
D.10.8 mV
Solution
Back EMF = $\frac{0.06}{2}\log\frac{0.12}{0.08} = 5.4 \times 10^{- 3}\text{ V}$
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