ElectrochemistryMedium

Question

On passing electricity through dilute H2SO4 solution, the mass of substances liberated at the cathode and anode are in the ratio of

Options

A.1:8
B.8:1
C.1:32
D.1:16

Solution

Cathode = H2, anode = O2 and $\frac{W_{H_{2}}}{W_{O_{2}}} = \frac{1}{8}$.

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