ElectrochemistryHard
Question
Calculate the solubility product of Co2[Fe(CN)6] in water at 25oC.
Given, conductivity of saturated solutions of Co2[Fe(CN)6] is 2.06 × 10-6 Ω-1 cm-1 and that of water used is 4.1 × 10-1 Ω-1 cm-1. The ionic molar conductivities of Co2+ and Fe(CN)64- are 86.0 Ω cm2 mol-1 and 444.0 Ω-1 cm2 mol-1, respectively.
Given, conductivity of saturated solutions of Co2[Fe(CN)6] is 2.06 × 10-6 Ω-1 cm-1 and that of water used is 4.1 × 10-1 Ω-1 cm-1. The ionic molar conductivities of Co2+ and Fe(CN)64- are 86.0 Ω cm2 mol-1 and 444.0 Ω-1 cm2 mol-1, respectively.
Options
A.7.87 × 10-7
B.7.87 × 10-6
C.7.87 × 10-8
D.7.87 × 10-9
Solution
KmCo2[F(CN)6 = 2.06 × 10-6 - 0.41 × 10-6 = 1.65 × 10-6
ΛmCo2[Fe(CN)6 = 2ΛmCo2+ + Λm[Fe(CN)6]4-
= 2 × 86 + 444 = 616 S cm2 mol-1
⇒ Λm = 1000
⇒ c = 27 × 10-6 M
KspCo2[Fe(CN)6] = 4c3 = 7.87 × 10-7 M3
ΛmCo2[Fe(CN)6 = 2ΛmCo2+ + Λm[Fe(CN)6]4-
= 2 × 86 + 444 = 616 S cm2 mol-1
⇒ Λm = 1000
⇒ c = 27 × 10-6 MKspCo2[Fe(CN)6] = 4c3 = 7.87 × 10-7 M3
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