ElectrochemistryHard
Question
Assuming that hydrogen behaves as an ideal gas, what is the EMF of the cell at 25°C if P1 = 600 mm and P2 = 420 mm: Pt | H2 (P1) | HCl | H2 (P2) | Pt? [Given: 2.303 RT/F = 0.06, log 7 = 0.85]
Options
A.−0.0045 V
B.−0.0 V
C.+0.0045 V
D.+0.0015 V
Solution
Net cell reaction = $H_{2}\left( P_{1} \right) \rightleftharpoons H_{2}\left( P_{2} \right)$
$E_{cell} = - \frac{0.06}{2}.\log\frac{420}{600} = + 0.0045\text{ V}$
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Consider the following cell reaction:2Fe(s) + O2(g) + 4H+(aq) → 2Fe2+(aq) + 2H2O(l) Eo = 1.67V At [Fe2+] = 10-3 M,...Calculate Ka of acetic acid if its 0.05 M solution has molar conductivity of 7.814 × 10−4 Ω−1 m2 mol−1 at 25°C. Given: $...What is the amount of chlorine evolved, when 2 amp of current is passed for 30 minutes in an aqueous solution of NaCl?...If a current of 1.0 A is drawn from the Daniel cell for 96.5 min, the cathode will gain in weight by (Cu = 63.5, Zn = 65...The current required to produce oxygen at the rate of 2.8 ml (0°C, 1 atm) per second during electrolysis of acidulated w...