ElectrochemistryHard

Question

If a current of 1.0 A is drawn from the Daniel cell for 96.5 min, the cathode will gain in weight by (Cu = 63.5, Zn = 65.4)

Options

A.1.905 g
B.1.962 g
C.3.81 g
D.3.924 g

Solution

Cu will deposit at cathode.

$n_{eq} = \frac{Q}{F} \Rightarrow \frac{w}{63.5} \times 2 = \frac{1 \times 96.5 \times 60}{96500} \Rightarrow w = 1.905\text{ gm}$

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