ElectrochemistryHard

Question

The current required to produce oxygen at the rate of 2.8 ml (0°C, 1 atm) per second during electrolysis of acidulated water is

Options

A.48.25 A/s

B.24.12 A/s

C.96.5 A/s

D.0.0048 A/s

Solution

n_eq = n × n-factor = $\frac{Q}{F}$

Or, $\frac{2.8}{22400} \times 4 = \frac{i \times 1}{96500} \Rightarrow i = 48.25\text{ A/sec}$

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