ElectrochemistryHard
Question
The current required to produce oxygen at the rate of 2.8 ml (0°C, 1 atm) per second during electrolysis of acidulated water is
Options
A.48.25 A/s
B.24.12 A/s
C.96.5 A/s
D.0.0048 A/s
Solution
neq = n × n-factor = $\frac{Q}{F}$
Or, $\frac{2.8}{22400} \times 4 = \frac{i \times 1}{96500} \Rightarrow i = 48.25\text{ A/sec}$
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