ThermochemistryHard

Question

Calculate the enthalpy of the following homogeneous gaseous reaction

CH3COCH3 + 2O2 → CH3COOH + CO2 + H2O

from the following data.

Bond energies (kJ/mol): C−H = 414; C−C = 348; C=O = 580; C−O = 354; O=O = 610; O−H = 462;

Magnitude of resonance energies (kJ/mol): COOH =118; CO2 = 140.

Options

A.348 kJ
B.168 kJ
C.−168 kJ
D.−348 kJ

Solution

$\Delta H_{\text{Required}} = \lbrack 6 \times 414 + 2 \times 348 + 580 + 2 \times 610\rbrack $$$ - \lbrack 3 \times 414 + 348 + 580 + 354 + 462 + 118 + 2 \times 580 + 140 + 2 \times 462\rbrack = - 348\text{ kJ}$$

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