ThermochemistryMedium
Question
Combustion of glucose takes place according to the equation :
C6H12O6 + 6O2 → 6CO2 + 6H2O, ᐃH = - 72 kcal
The energyrequired for production of 1.6g of glucose is [molecular mass of glucose is 180 gm]
C6H12O6 + 6O2 → 6CO2 + 6H2O, ᐃH = - 72 kcal
The energyrequired for production of 1.6g of glucose is [molecular mass of glucose is 180 gm]
Options
A.0.064 kcal
B.0.64 kcal
C.6.4 kcal
D.64 kcal
Solution
Formation of glucose will be the given by reaction taking place reverse direction.
6CO2 + 6H2P + 72Cal → C6H12O6 + 6O2 For production of 180 gm of glucose, heat energy is 72 k cals.
So required heat for 1.6 gm of glocose =
× 1.6 = 0.64 kcal
6CO2 + 6H2P + 72Cal → C6H12O6 + 6O2 For production of 180 gm of glucose, heat energy is 72 k cals.
So required heat for 1.6 gm of glocose =
× 1.6 = 0.64 kcalCreate a free account to view solution
View Solution FreeMore Thermochemistry Questions
The enthalpy change for a reaction does not depend upon...Study the following thermochemical equations.A → B; ΔH = +100 kcal B → C; ΔH = −80 kcalThe correct order of enthalpies o...The following are various ΔH values (kJ per mol), ΔfH (NaCl) = – 411.2; ΔfH (Na, g) = 107.3; ΔfH (Cl, g) = 121.7; ΔiH (N...Calculate the enthalpy of formation of I2O5(s) from the following data.(i) I2O5(s) + H2O(l) → 2HIO3(aq): ΔH = +4.0 kJ(ii...For the following reaction, C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l)Which of the following expression is incorrect?...