ThermochemistryHard
Question
Combustion of glucose takes place according to the equation :
C6H12O6 + 6O2 → 6CO2 + 6H2O, ᐃH = - 72 kcal
The energyrequired for production of 1.6g of glucose is [molecular mass of glucose is 180 gm]
C6H12O6 + 6O2 → 6CO2 + 6H2O, ᐃH = - 72 kcal
The energyrequired for production of 1.6g of glucose is [molecular mass of glucose is 180 gm]
Options
A.0.064 kcal
B.0.64 kcal
C.6.4 kcal
D.64 kcal
Solution
Formation of glucose will be the given by reaction taking place reverse direction.
6CO2 + 6H2P + 72Cal → C6H12O6 + 6O2 For production of 180 gm of glucose, heat energy is 72 k cals.
So required heat for 1.6 gm of glocose =
× 1.6 = 0.64 kcal
6CO2 + 6H2P + 72Cal → C6H12O6 + 6O2 For production of 180 gm of glucose, heat energy is 72 k cals.
So required heat for 1.6 gm of glocose =
× 1.6 = 0.64 kcalCreate a free account to view solution
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