ThermochemistryMedium
Question
Enthalpies of solution of BaCl2(s) and BaCl2·2H2O(s) are −20.6 kJ/mol and 8.8 kJ/mol, respectively. ΔH hydration of BaCl2(s) to BaCl2·2H2O(s) is
Options
A.−29.4 kJ
B.−11.8 kJ
C.29.6 kJ
D.11.8 kJ
Solution
$BaCl_{2}(s) + aq \rightarrow BaCl_{2}(aq);\Delta H = - 20.6\text{ kJ}$
$BaCl_{2}.2H_{2}O(s) + aq \rightarrow BaCl_{2}(aq);\Delta H = 8.8\text{ kJ} $$${\text{ Hence, for the reaction,} }{BaCl_{2}(s) + 2H_{2}O(l) \rightarrow BaCl_{2}.2H_{2}O(s); }{\Delta H = ( - 20.6) - (8.8) = - 29.4\text{ kJ}}$$
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