ThermochemistryMedium
Question
The heat of reaction for : C10H8(s) + 12O2(g) → 10CO2(g) + 4H2O(l) at constant volume is 1228.2 kcal at 25oC. The heat of reaction at contant pressure and same temperature is :
Options
A.-1228.2 kcal
B.-1229.3 kcal
C.-1232.9 kcal
D.1242.6 kcal
Solution
ᐃE = - 1228.2Kcal = 1228.2 × 103cal
ᐃH = ᐃE + ᐃnRT
1228.2 × 103 = (-2)(2)(298)
= - 1229392 cal
= - 1229.392 kcal
ᐃH = ᐃE + ᐃnRT
1228.2 × 103 = (-2)(2)(298)
= - 1229392 cal
= - 1229.392 kcal
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