Calculate ΔH for the following reaction at 298 K, Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) from the foll

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Calculate ΔH for the following reaction at 298 K, Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g) from the following thermochemical equations.

(i) 3Fe₂O₃(s) + CO(g) → 2Fe₃O₄(s) + CO₂(g): ΔH = −46.4 kJ

(ii) FeO(s) + CO(g) → Fe(s) + CO₂(g): ΔH = 9.0 kJ

(iii) Fe₃O₄(s) + CO(g) → 3FeO(s) + CO₂(g): ΔH = −41.0 kJ

Accepted Answer

From $\frac{1}{3} 	imes (i) + 2 	imes (ii) + \frac{2}{3} 	imes (iii):$ we get$\Delta H_{	ext{required}} = \frac{1}{3}( - 46.4) + 2(9.0) + \frac{2}{3}( - 41) = - 24.8	ext{ kJ}$

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