ThermochemistryHard

Question

Calculate ΔH for the following reaction at 298 K, Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) from the following thermochemical equations.

(i) 3Fe2O3(s) + CO(g) → 2Fe3O4(s) + CO2(g): ΔH = −46.4 kJ

(ii) FeO(s) + CO(g) → Fe(s) + CO2(g): ΔH = 9.0 kJ

(iii) Fe3O4(s) + CO(g) → 3FeO(s) + CO2(g): ΔH = −41.0 kJ

Options

A.−24.8 kJ
B.+24.8 kJ
C.−17.97 kJ
D.+17.97 kJ

Solution

From $\frac{1}{3} \times (i) + 2 \times (ii) + \frac{2}{3} \times (iii):$ we get

$\Delta H_{\text{required}} = \frac{1}{3}( - 46.4) + 2(9.0) + \frac{2}{3}( - 41) = - 24.8\text{ kJ}$

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