ThermochemistryHard
Question
Geological conditions are sometimes so extreme that quantities neglected in normal laboratory experiments take on an overriding importance. For example, consider the formation of diamond under geophysically typical conditions. The density of graphite is 2.4 g/cm3 and that of diamond is 3.6 g/cm3 at a certain temperature and 500 k bar. By how much does ΔUtrans differs from ΔHtrans for the graphite to diamond transition?
Options
A.83.33 kJ/mol
B.0.83 kJ/mol
C.8.33 × 107 kJ/mol
D.83.33 J/mol
Solution
$\Delta H - \Delta U = P.\Delta V = P\left\lbrack V_{D} - V_{G} \right\rbrack$
$= 500 \times 10^{3} \times 10^{5}\frac{N}{m^{2}}\left\lbrack \frac{12}{3.6} - \frac{12}{2.4} \right\rbrack \times 10^{- 6}\text{ }\text{m}^{3} $$$= - 8.33 \times 10^{4}\text{ J/mol}$$
Create a free account to view solution
View Solution FreeMore Thermochemistry Questions
Formation of ozone from oxygen is an endothermic process. In the upper atmosphere, ultraviolet is the source of energy t...Enthalpy of neutralization of the reaction between CH3COOH(aq) and NaOH(aq) is −13.2 kcal/eq and that of the reaction be...In the exothermic reaction, the enthalpy of reaction is always :...The enthalpy change for a reaction does not depend upon...A quantity that cannot be directly measured is...