ThermochemistryHard

Question

The molar enthalpy of vaporization of benzene at its boiling point (353 K) is 7.4 kcal/mol. The molar internal energy change of vaporization is

Options

A.7.4 kcal/mol

B.8.106 kcal/mol

C.6.694 kcal/mol

D.62.47 kcal/mol

Solution

$w = - nRT = - 1 \times 2 \times 353 = - 706\text{ cal}$

$\therefore\Delta U = q + w = 7.4 + \left( - \frac{706}{1000} \right) = 6.694\text{ kcal/mol}$

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