ThermochemistryHard
Question
The molar enthalpy of vaporization of benzene at its boiling point (353 K) is 7.4 kcal/mol. The molar internal energy change of vaporization is
Options
A.7.4 kcal/mol
B.8.106 kcal/mol
C.6.694 kcal/mol
D.62.47 kcal/mol
Solution
$w = - nRT = - 1 \times 2 \times 353 = - 706\text{ cal}$
$\therefore\Delta U = q + w = 7.4 + \left( - \frac{706}{1000} \right) = 6.694\text{ kcal/mol}$
Create a free account to view solution
View Solution FreeMore Thermochemistry Questions
The reaction CH4(g) + Cl2(g) → CH3Cl(g) + HCl (g) has ᐃH = - 25 kcalFrom the given, data, what is the bond e...When carbon is burnt in a definite amount of oxygen, the product will be CO, if excess amount of carbon is present and t...If the enthalpy of formation and enthalpy of solution of HCl (g) are - 92.3 kJ/mol and - 75.14 kJ/mol respectively then ...The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 250C are -400 kJ/mol, -300 kJ/mol & -1300 k...For the reaction C(s) + ½ O2(g) → CO(g),...