ThermochemistryHard
Question
The enthalpy change involved in the oxidation of glucose is −2880 kJ/mol. Twenty five per cent of this energy is available for muscular work. If 100 kJ of muscular work is needed to walk 1 km, what is the maximum distance that a person will be able to walk after eating 120 g of glucose?
Options
A.19.2 km
B.9.6 km
C.2.4 km
D.4.8 km
Solution
Heat released from 120 gm glucose $= \frac{2880}{180} \times 120 = 1920\text{ kJ}$
$\therefore$ Distance $\frac{1920}{100} \times \frac{25}{100} = 4.8\text{ km}$
Create a free account to view solution
View Solution FreeMore Thermochemistry Questions
AB, A2 and B2 are diatomic molecules. If the bond enthalpies of A2, AB and B2 are in the ratio 2:2:1 and enthalpy of for...Enthalpy of formation of HF and HCl are - 161 kJ and - 92 kJ respectively. Which of thefollowing statements is incorrect...Heat of neutralisation of CsOH with all strong acid is 13.4 kcal mol-1. The heat released on neutralisation of CsOH with...A quantity of 0.3 g of carbon was converted into CO2 producing 2400 cal of heat. When 0.6 g of carbon was converted to C...A quantity of 1.6 g sample of NH4NO3 is decomposed in a bomb calorimeter. The temperature of the calorimeter decreases b...