ΔfHo for NF3(g) is −113 kJ/mol. Bond energy for the N–F bond is 273.5 kJ/mol. The bond energies of N

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ΔfHo for NF3(g) is −113 kJ/mol. Bond energy for the N–F bond is 273.5 kJ/mol. The bond energies of N2 and F2, if their magnitudes are in the ratio 6:1, are respectively,

Accepted Answer

$\frac{1}{2}N_{2}(g) + \frac{3}{2}F_{2}(g) \rightarrow NF_{3}(g);\Delta H = - 113\text{ kJ}$

Now, $- 113 = \left\lbrack \frac{1}{2} \times x + \frac{3}{2} \times \frac{x}{6} \right\rbrack - (3 \times 273.5)$

$\therefore x = 943.33\text{ kJ}$

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