ThermochemistryMedium

Question

The heat evolved in the combustion of glucose C6H12O6 is −680 kcal/mol. The mass of CO2 produced, when 170 kcal of heat is evolved in the combustion of glucose is

Options

A.45 g
B.66 g
C.11 g
D.44 g

Solution

$C_{6}H_{12}O_{6}(s) + 6O_{2}(g) \rightarrow 6CO_{2}(g) + 6H_{2}O(l); \Delta H = - 680\text{ Kcal}$

For 680 Kcal, 6 × 44 gm CO2 is produced. Hence, for 170 Kcal, mass of CO2 produced $= \frac{6 \times 44}{680} \times 170 = 66\text{ gm}$

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