ThermochemistryHard
Question
Calculate the free energy change for the reaction: H2(g) + Cl2(g) → 2HCl(g) by using the following data at the reaction temperature of 27o C.
Bond enthalpies (kJ/mol): H − H = 435; Cl − Cl = 240; H − Cl = 430
Entropies (J/K-mol): H2 = 130; Cl2 = 222; HCl = 186
Options
A.−185 kJ
B.−20 kJ
C.−179 kJ
D.−191 kJ
Solution
From $(ii) - (i)$;
$\Delta G^{o} = ( - 12.4) - ( - 29.2) = + 16.8\text{ kJ}$
Create a free account to view solution
View Solution FreeMore Thermochemistry Questions
Consider the following reactions : C (s) + O2 (g) → CO2 (g) + x kJ CO (g) + O2 (g) → CO2 (g) + y kJThe heat ...The polymerization of ethylene to linear polyethylene is represented by the reactionnCH2 = CH2→ (−CH2−CH2−)nwhere n has ...Standard enthalpy of formation of gaseous ethane, ethene and benzene from gaseous atoms are −2839, −2275 and −5506 kJ/ m...Determine ᐃUo at 300 K for the following reaction using the listed enthalpies of reaction :4CO(g) + 8H2(g) →...The molar enthalpy of vaporization of benzene at its boiling point (353 K) is 7.4 kcal/mol. The molar internal energy ch...