ThermochemistryMedium
Question
Calculate the free energy change for the reaction: H2(g) + Cl2(g) → 2HCl(g) by using the following data at the reaction temperature of 27o C.
Bond enthalpies (kJ/mol): H − H = 435; Cl − Cl = 240; H − Cl = 430
Entropies (J/K-mol): H2 = 130; Cl2 = 222; HCl = 186
Options
A.−185 kJ
B.−20 kJ
C.−179 kJ
D.−191 kJ
Solution
From $(ii) - (i)$;
$\Delta G^{o} = ( - 12.4) - ( - 29.2) = + 16.8\text{ kJ}$
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