ThermochemistryHard

Question

When 0.18 g of glucose was burnt in a bomb calorimeter, the temperature rose by 4 K. The heat capacity of the calorimeter system is (ΔCH ° = –2.8 × 106 J/ mol glucose)

Options

A.700 J/K
B.700 kJ/K
C.126 J/K
D.7.0 kJ/K

Solution

Heat released by reaction = c · ΔT

Or $\frac{2.8 \times 10^{6}}{180} \times 0.18 = c \times 4 \Rightarrow c = 700\text{ J/K}$

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