ThermochemistryMedium

Question

When 0.18 g of glucose was burnt in a bomb calorimeter, the temperature rose by 4 K. The heat capacity of the calorimeter system is (ΔCH ° = –2.8 × 106 J/ mol glucose)

Options

A.700 J/K
B.700 kJ/K
C.126 J/K
D.7.0 kJ/K

Solution

Heat released by reaction = c · ΔT

Or $\frac{2.8 \times 10^{6}}{180} \times 0.18 = c \times 4 \Rightarrow c = 700\text{ J/K}$

Create a free account to view solution

View Solution Free
Topic: Thermochemistry·Practice all Thermochemistry questions

More Thermochemistry Questions

The ΔGo values for the hydrolysis of creatine phosphate (creatine-P) and glucose-6-phosphate (G-6-P) are(i) Creatine-P +...Calculate the standard free energy change for the ionization HF(aq) → H+ (aq) + F– (aq) from the following data.HF(aq) →...Calculate the enthalpy of formation of I2O5(s) from the following data.(i) I2O5(s) + H2O(l) → 2HIO3(aq): ΔH = +4.0 kJ(ii...From the following thermochemical equations, find out the bond dissociation enthalpy of CH3−H bond.CH3I(g) → CH3(g) + I(...A + BA gives iodoform test. ′B′ is heated with excess of H-I. then ′C′ is obtained A and C are :...