ThermochemistryHard
Question
In a flask, colourless N2O4 is in equilibrium with brown coloured NO2. At equilibrium, when the flask is heated at 373 K, the brown colour deepens and on cooling it becomes less coloured. The change in enthalpy for this reaction is
Options
A.negative
B.positive
C.zero
D.unpredictable
Solution
$N_{2}O_{4} \rightleftharpoons 2N{O_{2}}_{\left( \text{Brown} \right)}$
On heating, colour deepens means reaction is endothermic ($\Delta H = + \text{ve}$)
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