Calculate the enthalpy of formation (in kcal/mol) of gaseous HCl using the following data.Substance

Question

Calculate the enthalpy of formation (in kcal/mol) of gaseous HCl using the following data.

Substance NH₃(g) HCl(g) NH₄Cl(s)

Heat of formation −11 X −75

Heat of solution −8.5 −17.5 +3.9 kcal

NH₃ (aq) + HCl (aq) → NH₄Cl (aq): ΔH = −12 kcal

Accepted Answer

$- 12 = \left\lbrack ( - 75) + (3.9) ightbrack - \left\lbrack ( - 11) + ( - 8.5) + x + ( - 17.5) ightbrack$$	herefore X = - 22.1	ext{ kcal/mol}$

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