SolutionHard
Question
A solution of ‘x’ mole of sucrose in 100 g of water freezes at − 0.2°C. As ice separates out, the freezing point goes down to − 0.25°C. How many grams of ice would have separated?
Options
A.18 g
B.20 g
C.80 g
D.25 g
Solution
$\Delta T_{f} = K_{f}.m$
$\therefore 0.2 = K_{f} \times \frac{x}{100/1000}\text{ and 0.25 = }K_{f} \times \frac{x}{y/1000}$
∴ Mass of ice separated out = 100 – y = 20 gm
Create a free account to view solution
View Solution FreeMore Solution Questions
At 323 K, the vapour pressure in millimeters of mercury of a methanol-ethanol solution is represented by the equation p ...Relative decrease in vapour pressure of an aqueous solution containing 2 moles [Cu(NH3)3Cl] Cl in 3 moles H2O is 0.50. O...Each of the following pair shows a positive deviation from the Raoult’s law except...The boiling point of a 2% (w/w) aqueous solution of a non-volatile and non-electrolyte solute is 0.102°C higher than tha...Consider the following reactions.(Hot solution)In the above reactions, and X are respectively....