SolutionHard
Question
An aqueous solution of a non-volatile and nonelectrolyte solute (molecular mass = 150) boils at 373.26 K. The composition of solution, in terms of mass percent of the solute, is (Kb of water = 0.52)
Options
A.50%
B.7.5%
C.6.98%
D.75%
Solution
$\Delta T_{b} = K_{b}.m \Rightarrow 0.26 = 0.52 \times \frac{w_{1}/150}{w_{2}/1000} \Rightarrow \frac{w_{1}}{w_{2}} = \frac{3}{40}$
∴ Mass percent of solute = $\frac{w_{1}}{w_{1} + w_{2}} \times 100\% = 6.98\%$
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