SolutionHard
Question
When 2 g non-volatile hydrocarbon containing 94.4% carbon by mass is dissolved in 100 g of benzene, the vapour pressure of benzene at 30°C is lowered from 89.78 mm to 89.0 mm. The molecular formula of the hydrocarbon is
Options
A.C12H34
B.C13H22
C.C14H12
D.C14H10
Solution
$\frac{P^{o} - P}{P} = \frac{n_{1}}{n_{2}} \Rightarrow \frac{89.78 - 89}{89} = \frac{2/M}{100/78} \Rightarrow M = 178$
Now, the number of C-atoms in each molecule $= \frac{178 \times \frac{94.4}{100}}{12} = 14$
and the number of H-atoms in each molecule $= \frac{178 \times \frac{5.6}{100}}{1} = 10$
∴ Hydrocarbon is C14H10.
Create a free account to view solution
View Solution FreeMore Solution Questions
The freezing point of equimolar aqueous solution will be highest for...Low concentration of oxygen in blood and tissues of people living at high altitude is due to...The vapour pressure of water at 20oC is 17.5 mm Hg. If 18 g of glucose (C6H12O6) is added to 178.2 g of water at 20oC, t...18 g of glucose (C6H12O6) is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at 100oC ...A 5.25 % solution of a substance is isotonic with a 1.5% solution of urea (molar mass = 60 g mol-1) in the same solvent....