SolutionMedium
Question
An aqueous solution containing 0.25 moles of a non-volatile but strong electrolyte solute ‘X’ in 500 g water freezes at −2.79°C. The number of ions furnished in water per formula unit of ‘X’ is (Kf = 1.86)
Options
A.1
B.2
C.3
D.4
Solution
$\Delta T_{f\left( \text{theo} \right)} = K_{f}.m = 1.86 \times \frac{0.25}{500/1000} = 0.93\text{ K}$
Now, $i = \frac{\Delta T_{f\left( \text{exp} \right)}}{\Delta T_{f\left( \text{theo} \right)}} = \frac{2.79}{0.93} = 3$
As, $i = 1 + \alpha(n - 1) \Rightarrow 3 = 1 + 1(n - 1) \Rightarrow n = 3$
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