SolutionHard
Question
For the given electrolyte AxBy, the degree of dissociation ′a′ can be given as
Options
A.α = 
B.i = (1 - α) + xα + yα
C.α = 
D.None
Solution
AxBy ⇋ xAm+ + yBn+
Initial moles n o o
At eq b. n(1-α) nxα nyα
i =
i = (1- α) + xα + yα
It can also seen that all other expressions imply the same thing.
(A) α =
(B) i = (1 - α) + xα + yα. (C) 
Initial moles n o o
At eq b. n(1-α) nxα nyα
i =
i = (1- α) + xα + yα
It can also seen that all other expressions imply the same thing.
(A) α =
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