SolutionHard
Question
For the given electrolyte AxBy, the degree of dissociation ′a′ can be given as
Options
A.α = 
B.i = (1 - α) + xα + yα
C.α = 
D.None
Solution
AxBy ⇋ xAm+ + yBn+
Initial moles n o o
At eq b. n(1-α) nxα nyα
i =
i = (1- α) + xα + yα
It can also seen that all other expressions imply the same thing.
(A) α =
(B) i = (1 - α) + xα + yα. (C) 
Initial moles n o o
At eq b. n(1-α) nxα nyα
i =
i = (1- α) + xα + yα
It can also seen that all other expressions imply the same thing.
(A) α =
Create a free account to view solution
View Solution FreeMore Solution Questions
If vapour pressures of pure liquids ′A′ & ′B′ are 300 and 800 torr respectively at 25oC. When th...The normal freezing point of nitrobenzene is 278.82 K. A non-volatile solute is dissolved in it and a solution of molali...Sodium nitroprusside solution can be used to detect which of the following acid radicals -...Addition of 4.0 g of a non-volatile solute to 54.0 g water results in a lowering of vapour pressure by 1.0%. What is the...Exactly 1g of urea dissolved in 75 g of water give a solution that boils at 100.114oC at 760 torr. The molecular weight ...