SolutionHard
Question
Vapour pressure of CCl4 at 25oC is 143 mmHg. 0.5 g of a non-voltaile solute (molar mass = 65 mol-1) is dissolved in 100 mL of CCl4 (density = 1.538 g mL-1). Vapour pressure of solution is
Options
A.141.9 mmHg
B.94.4 mmHg
C.99.3 mmHg
D.144.1 mmhg
Solution
Wt .of CCl4 = 1.538 × 100 = 153.8 gm
so moles of CCl4 =
≈ 1
moles of solute =
= 0.00769
Now
or
PS = 141.9 mm Hg.
so moles of CCl4 =
≈ 1moles of solute =
= 0.00769Now
or
PS = 141.9 mm Hg.
Create a free account to view solution
View Solution FreeMore Solution Questions
80 mL of a hydrocarbon on mixing with 264 mL of oxygen in a closed U-tube undergoes complete combustion. The residual ga...The ratio between lowering of vapour pressure of solution and mole fraction of solute is equal to...Barium ions, CN- and Co2+ form an ionic complex. If that is supposed to be 75% ionised in water with vant Hoff factor (i...The boiling point of an azeotropic mixture of water and ethanol is less than that of water and ethanol, separately. The ...At the same temperature, each of the following solution has the same osmotic pressure except...