SolutionHard
Question
Vapour pressure of CCl4 at 25oC is 143 mmHg. 0.5 g of a non-voltaile solute (molar mass = 65 mol-1) is dissolved in 100 mL of CCl4 (density = 1.538 g mL-1). Vapour pressure of solution is
Options
A.141.9 mmHg
B.94.4 mmHg
C.99.3 mmHg
D.144.1 mmhg
Solution
Wt .of CCl4 = 1.538 × 100 = 153.8 gm
so moles of CCl4 =
≈ 1
moles of solute =
= 0.00769
Now
or
PS = 141.9 mm Hg.
so moles of CCl4 =
≈ 1moles of solute =
= 0.00769Now
or
PS = 141.9 mm Hg.
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