SolutionHard
Question
The vapour pressure of water at room temperature is lowered by 5% on dissolving a non-volatile solute in it. The molality of the solution is
Options
A.2.0
B.1.4
C.2.78
D.2.92
Solution
$\frac{P^{o} - P}{P} = \frac{n_{1}}{n_{2}} \Rightarrow \frac{5}{95} = \frac{n_{1}}{n_{2}}$
∴ Molality of solution = $\frac{n_{1}}{n_{2} \times 18} \times 1000 = 2.92$
Create a free account to view solution
View Solution FreeMore Solution Questions
Which is/are true about ideal solutions ?...Which one of the statements given below concerning properties of solution, describes a colligative effect ?...Ratio of ᐃTb / Kb of 6% AB2 and 9% A2B (AB2 and A2B both are non-electrolytes) is 1 mol/kg in both cases. Hence, a...The vapour pressure of a substance of low volatility can be measured by passing an unreactive gas over a sample of the s...A sample of air is saturated with benzene (vapor pressure = 100 mm Hg at 298 K) at 298K, 750mm Hg pressure. If it is iso...