SolutionMedium
Question
The vapour pressure of water at room temperature is lowered by 5% on dissolving a non-volatile solute in it. The molality of the solution is
Options
A.2.0
B.1.4
C.2.78
D.2.92
Solution
$\frac{P^{o} - P}{P} = \frac{n_{1}}{n_{2}} \Rightarrow \frac{5}{95} = \frac{n_{1}}{n_{2}}$
∴ Molality of solution = $\frac{n_{1}}{n_{2} \times 18} \times 1000 = 2.92$
Create a free account to view solution
View Solution FreeMore Solution Questions
At 100oC the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, theboiling point...A glucose solution is isopiestic with blood. What is the osmolarity of glucose solution?...Select correct statements :...How many grams of glucose (C6H12O6) should be dissolved in 0.5 kg of water at 25°C to reduce the vapour pressure of the ...Isohydric solutions are the solutions having the same concentration of hydronium ion. If 0.2 M-HA solution is isohydric ...