SolutionHard
Question
The vapour pressure of a solvent is decreased by 10 mm of Hg when a non-volatile solute was added to the solvent. The mole fraction of solute in the solution is 0.2. What would be the mole fraction of solvent if decrease in vapour pressure is 20 mm of Hg?
Options
A.0.8
B.0.6
C.0.4
D.0.7
Solution
$P^{o} - P = X_{1}.P^{o}$
$10 = 0.2 \times P^{o}(1) $$${20 = X_{1} \times P^{o}(2) }{\text{From }(1)\text{ and }(2):X_{1} = 0.4 \Rightarrow X_{2} = X_{\text{solvent}} = 0.6}$$
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