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Question
An aqueous solution of sucrose is 0.5 molal. What is the vapour pressure of water above this solution? The vapour pressure of pure water is 25.0 mm Hg at this temperature.
Options
A.24.8 mm Hg
B.0.45 mm Hg
C.2.22 mm Hg
D.20.3 mm Hg
Solution
$P = X_{2}.P^{o} = \frac{1000/18}{0.5 + \frac{1000}{18}} \times 25 = 24.78\text{ mm Kg}$
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