The vapour pressure of pure benzene at 88°C is 960 mm and that of toluene at the same temperature is

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The vapour pressure of pure benzene at 88°C is 960 mm and that of toluene at the same temperature is 380 mm of benzene. At what mole fraction of benzene, the mixture will boil at 88°C?

Accepted Answer

$P_{	ext{total}} = X_{	ext{Benzene}}.P_{	ext{Benzene}}^{o} + X_{	ext{Toulene}}.P_{	ext{Toulene}}^{o}$Or, $760 = x 	imes 960 + (1 - x) 	imes 380 \Rightarrow x = 0.655$

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