SolutionHard
Question
The vapour pressure of pure benzene at 88°C is 960 mm and that of toluene at the same temperature is 380 mm of benzene. At what mole fraction of benzene, the mixture will boil at 88°C?
Options
A.0.655
B.0.345
C.0.05
D.0.25
Solution
$P_{\text{total}} = X_{\text{Benzene}}.P_{\text{Benzene}}^{o} + X_{\text{Toulene}}.P_{\text{Toulene}}^{o}$
Or, $760 = x \times 960 + (1 - x) \times 380 \Rightarrow x = 0.655$
Create a free account to view solution
View Solution FreeMore Solution Questions
A Solution of sucrose (molar mass = 342 gm-mol-1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. ...The solution having higher osmotic pressure than the reference solution is called...Benzene and toluene form nearly ideal solutions. At 20oC, the vapour pressure of benzene is 75 torr and that of toluene ...Calculate the osmotic pressure of the solution prepared in the above question T = 300 K, (R = 0.082 L atm mol-1K-1)...How many moles of sucrose should be dissolved in 500 gms of water so as to get a solution which has a difference of 104o...