Ionic EquilibriumHard
Question
A volume of 250 ml of saturated clear solution of CaC2O4(aq) requires 6.0 ml of 0.001 M-KMnO4 in acidic medium for complete oxidation of C2O42− ions. What is the value of Ksp for CaC2O4?
Options
A.3.6 × 10–9
B.6 × 10–5
C.5.76 × 10–10
D.1.44 × 10–8
Solution
$\left\lbrack C_{2}O_{4}^{2 -} \right\rbrack = \frac{6 \times 0.001 \times 5}{250 \times 2} = 6 \times 10^{- 5}\text{ M}$
$\therefore K_{sp} = \left( 6 \times 10^{- 5} \right)^{2} = 3.6 \times 10^{- 9}$
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
The formation constant of Cu(NH3)42+ is 1.25 × 1012. What will be the equilibrium concentration of Cu2+ if 0.0125 moles ...A buffer solution is prepared in which the concentration of NH3 is 0.30 M and the concentration of NH4+ is 0.20 M. If th...When 0.1 mole solid NaOH is added in 1lt of 0.1M NH3(aq) then which statement is going to wrong?(Kb = 2 × 10-5, log...The pH of water is 7.0 at 25oC. If water is heated to 70oC, then...Which is not true about acetaminophen ?...