Ionic EquilibriumHard
Question
A volume of 250 ml of saturated clear solution of CaC2O4(aq) requires 6.0 ml of 0.001 M-KMnO4 in acidic medium for complete oxidation of C2O42− ions. What is the value of Ksp for CaC2O4?
Options
A.3.6 × 10–9
B.6 × 10–5
C.5.76 × 10–10
D.1.44 × 10–8
Solution
$\left\lbrack C_{2}O_{4}^{2 -} \right\rbrack = \frac{6 \times 0.001 \times 5}{250 \times 2} = 6 \times 10^{- 5}\text{ M}$
$\therefore K_{sp} = \left( 6 \times 10^{- 5} \right)^{2} = 3.6 \times 10^{- 9}$
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