Ionic EquilibriumHard

Question

Morphine (C17H19NO3) is administered medically to relieve pain. It is a naturally occurring base or alkaloid. What is the pH of a 0.0025 M solution of morphine at 25°C? The base-ionization constant Kb is 1.6 × 10–6 at 25°C. (log 2 = 0.3)

Options

A.4.2
B.9.8
C.3.7
D.10.3

Solution

$\left\lbrack OH^{-} \right\rbrack = \sqrt{K_{b} \times C} = \sqrt{1.6 \times 10^{- 6} \times 0.0025} = \sqrt{4 \times 10^{- 9}}\text{ M}$

$P^{OH} = - \log\sqrt{4 \times 10^{- 9}} = 4.2 \Rightarrow P^{H} = 9.8$

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