Ionic EquilibriumMedium
Question
Solubility product constant (Ksp) of salts of types MX, MX2 and M3X at temperature, T are 4.0 × 10−8, 3.2 × 10−14 and 2.7 × 10−15, respectively. Solubilities (in M) of the salts at temperature, T, are in the order
Options
A.MX > MX2 > M3X
B.M3X > MX2 > MX
C.MX2 > M3X > MX
D.MX > M3X > MX2
Solution
For MX: Solubility = $\sqrt{K_{sp}} = \sqrt{4 \times 10^{- 8}} = 2 \times 10^{- 4}\text{ M}$
For MX2: Solubility = $\left( \frac{K_{sp}}{4} \right)^{1/3} = \left( \frac{3.2 \times 10^{- 14}}{4} \right)^{1/3} = 2 \times 10^{- 5}\text{ M}$
For M3X: Solubility = $\left( \frac{K_{sp}}{27} \right)^{1/4} = \left( \frac{2.7 \times 10^{- 15}}{27} \right)^{1/3} = 1 \times 10^{- 4}\text{ M}$
∴ Order of solubility = MX2 < M3X < MX
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