Ionic EquilibriumHard
Question
What is the difference in pH for 1/3 and 2/3 stages of neutralisation of 0.1 M CH3COOH with 0.1 M NaOH.
Options
A.2 log 3
B.2 log (1/4)
C.2 log (2/3)
D.2 log 2
Solution
CH3COOH + OH- → CH3COO- + H2O
Difference in pH between
stages of neutralisation = 
= 2 log 2
Difference in pH between
stages of neutralisation = = 2 log 2Create a free account to view solution
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