Ionic EquilibriumMedium
Question
If ionization of XaYb takes place then, the number of Y–a ions will be equal to
Options
A.b/a times of X+b
B.a/b times of X+b
C.b/a times of Xa+
D.equal to X+b
Solution
$X_{a}Y_{b} \rightleftharpoons \underset{a\text{ mole}}{aX^{b +}} + \underset{b\text{ mole}}{bY^{a -}}$
$\therefore\text{Moles of }Y^{a -} = \frac{b}{a} \times \text{moles of }X^{b +}$
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