Ionic EquilibriumHard

Question

The concentration of acetate ions in 1 M acetic acid (Ka = 2 × 10−5) solution containing 0.1 M HCl is

Options

A.2 × 10–1 M
B.2 × 10–3 M
C.2 × 10–4 M
D.4.4 × 10–3 M

Solution

CH3COOH $\rightleftharpoons$ CH3COO– + H+

1M 0 0.1 M

Equilibrium 1 – x x 0.1 + x

$\simeq$1M $\simeq$0.1 M

Now, $K_{a} = \frac{\left\lbrack CH_{3}COO^{-} \right\rbrack\left\lbrack H^{+} \right\rbrack}{\left\lbrack CH_{3}COOH \right\rbrack} \Rightarrow 2 \times 10^{- 5} = \frac{x \times 0.1}{1}$

⇒ x = 2 × 10–4 M

Create a free account to view solution

View Solution Free
Topic: Ionic Equilibrium·Practice all Ionic Equilibrium questions

More Ionic Equilibrium Questions

The vapour pressure of a given liquid will decrease if....A buffer solution is prepared by mixing ′a′ moles of CH3COONa and ′b′ moles of CH3COOH such that...pH of a 0.1 M monobasic acid is measured to be 2. Its osmotic pressure at a given temperature TK is ?...One mole of CH3COOH and one mole of C2H5OH reacts to produce mol of CH3COOC2H2. The equilibrium constant is:...Morphine (C17H19NO3) is administered medically to relieve pain. It is a naturally occurring base or alkaloid. What is th...